- local x1 = 0
- local x2 = 0
- local x4 = 1
- local x6 = 1
-
- forvalue i = 1/20490 {
- if num == `i' {
- forvalue n = 0/18 {
- capture noisily replace f123a_1_`x1'_ = . if f_2_sel_`n'_ ==1 & num == `i' & f123a_1_`x1'_ ~=.
- capture noisily replace f126_a1_`x2'_ = . if f_2_sel_`n'_ ==1 & num == `i' & f126_a1_`x2'_ ~=.
- capture noisily replace f128_`x4'_ = . if f_2_sel_`n'_ ==1 & num == `i' & f128_`x4'_ ~=.
- capture noisily replace f129a_`x6'_ = . if f_2_sel_`n'_ ==1 & num == `i' & f129a_`x6'_ ~=.
-
- if f_3_`n'_==1 {
- local x1 = `x1'+1
- }
- else if f_3_`n'_==2 {
- local x2 = `x2'+1
- }
- else if f_3_`n'_==3 {
- local x2 = `x3'+1
- }
- else if f_3_`n'_==4 {
- local x4 = `x4'+1
- }
- else if f_3_`n'_==6 {
- local x6 = `x6'+1
- }
- else {
- continue
- }
- }
- }
- local x1 = 0
- local x2 = 0
- local x4 = 1
- local x6 = 1
- }
- f_2_sel_`n' 代表第1/n份工作是否在继续工作是否还在继续(1代表停止)
- f123a_1_`x1', f126_a1_`x2'...分别对应第几份工作获得的income
- f_3_`n'_==1,2,...6对应的六种不同的工作类型,2和3获得的工资都在 f126_a1_`x2里,而第五份是无收入工资,也就没有对应的varlist
但是现在的代码写出来却全是
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求大神们指教问题出在哪里。。。