各位大神，我写的语句有问题吗？
TITLE: this is an example of a CFA with
continuous factor indicators;
DATA: FILE IS 未标题3.dat;
VARIABLE:
NAMES ARE ID a1-a13 SEX AGE EDUCATION b1-b3 b5-b10;
usevariables are EDUCATION b1-b2 b9;
define:
b1b9=b1*b9;
b2b9=b2*b9;
analysis:
TYPE = RANDOM;
ALGORITHM = INTEGRATION;
model:
x by b1 b2;
m by b9;
y by EDUCATION;
xm by b1*b9 b2*b9;
y on x;
y on m;
y on xm;
output:
STANDARDIZED;

在Mplus中的输出是这样的：
MODEL RESULTS

Estimate

X BY
B1 1.000
B2 1.037

M BY
B9 1.000

Y BY
EDUCATION 1.000

XM BY
B1 1.105
B9 0.987
B2 0.914

Y ON
X -0.081
M 0.025
XM -0.083

M WITH
X -0.132

XM WITH
X 0.133
M 0.041

Intercepts
EDUCATION 1.640
B1 -0.003
B2 -0.004
B9 0.002

Variances
X 0.194
M 0.098
XM 0.160

Residual Variances
EDUCATION 0.321
B1 0.798
B2 0.695
B9 0.434
Y 0.139


MODEL COMMAND WITH FINAL ESTIMATES USED AS STARTING VALUES

x BY b1@1;
x BY b2*1.03745;
m BY b9@1;
y BY education@1;
xm BY b1*1.10486;
xm BY b9*0.98697;
xm BY b2*0.91444;

y ON x*-0.08077;
y ON m*0.02472;
y ON xm*-0.08250;

m WITH x*-0.13226;
xm WITH x*0.13293;
xm WITH m*0.04086;

[ education*1.63955 ];
[ b1*-0.00304 ];
[ b2*-0.00397 ];
[ b9*0.00208 ];

education*0.32105;
b1*0.79779;
b2*0.69501;
b9*0.43425;
x*0.19390;
m*0.09803;
y*0.13883;
xm*0.15998;



TECHNICAL 1 OUTPUT


PARAMETER SPECIFICATION


NU
EDUCATIO B1 B2 B9
________ ________ ________ ________
1 1 2 3 4


LAMBDA
X M Y XM
________ ________ ________ ________
EDUCATIO 0 0 0 0
B1 0 0 0 5
B2 6 0 0 7
B9 0 0 0 8


THETA
EDUCATIO B1 B2 B9
________ ________ ________ ________
EDUCATIO 9
B1 0 10
B2 0 0 11
B9 0 0 0 12


ALPHA
X M Y XM
________ ________ ________ ________
1 0 0 0 0


BETA
X M Y XM
________ ________ ________ ________
X 0 0 0 0
M 0 0 0 0
Y 13 14 0 15
XM 0 0 0 0


PSI
X M Y XM
________ ________ ________ ________
X 16
M 17 18
Y 0 0 19
XM 20 21 0 22


STARTING VALUES


NU
EDUCATIO B1 B2 B9
________ ________ ________ ________
1 1.640 -0.003 -0.004 0.002


LAMBDA
X M Y XM
________ ________ ________ ________
EDUCATIO 0.000 0.000 1.000 0.000
B1 1.000 0.000 0.000 1.000
B2 1.000 0.000 0.000 1.000
B9 0.000 1.000 0.000 1.000


THETA
EDUCATIO B1 B2 B9
________ ________ ________ ________
EDUCATIO 0.232
B1 0.000 0.740
B2 0.000 0.000 0.645
B9 0.000 0.000 0.000 0.384


ALPHA
X M Y XM
________ ________ ________ ________
1 0.000 0.000 0.000 0.000


BETA
X M Y XM
________ ________ ________ ________
X 0.000 0.000 0.000 0.000
M 0.000 0.000 0.000 0.000
Y 0.000 0.000 0.000 0.000
XM 0.000 0.000 0.000 0.000


PSI
X M Y XM
________ ________ ________ ________
X 0.050
M 0.000 0.050
Y 0.000 0.000 0.050
XM 0.000 0.000 0.000 0.050
我表示看不懂，不知道为什么是这样

输出的图像如附件所示