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Common Lisp Recipes [推广有奖]

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ReneeBK 发表于 2016-8-14 22:47:42 |AI写论文

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ReneeBK(未真实交易用户) 发表于 2016-8-14 22:48:15
  1. 4-1. Using Arbitrarily Large Integers
  2. Problem
  3. You are afraid of integer overflow.
  4. Solution
  5. Don’t be!
  6. Here’s a session showing off a few computations with large integers:
  7. ;; see <http://en.wikipedia.org/wiki/Fermat_number>
  8. * (defun fermat (n) (1+ (expt 2 (expt 2 n))))
  9. FERMAT
  10. * (fermat 7)
  11. 340282366920938463463374607431768211457
  12. * (fermat 8)
  13. ;; wrapped around so that it fits on the book page
  14. 1157920892373161954235709850086879078532699846656405640394575840079
复制代码
藤椅
ReneeBK(未真实交易用户) 发表于 2016-8-14 22:49:19
  1. 4-2. Understanding Fixnums
  2. Problem
  3. You’ve learned that COMMON LISP has integers that can be as large as you need, but
  4. you want to know whether it also has “small” integers like in C or JAVA that fit into
  5. the machine’s registers.
  6. Solution
  7. It has. And these numbers are called fixnums. If you run the following code, the
  8. output should be (T NIL T NIL T T) no matter which Lisp you use:7
  9. (loop for n in (list most-positive-fixnum (1+ most-positive-fixnum))
  10. append (loop for type in ’(fixnum bignum integer)
  11. collect (typep n type)))
复制代码
板凳
ReneeBK(未真实交易用户) 发表于 2016-8-14 22:50:17
  1. 4-3. Performing Modular Arithmetic
  2. Problem
  3. You want modular arithmetic the way it is implemented in your computer’s CPU.
  4. Solution
  5. Once you know about the MOD function, it seems pretty obvious that if you want to,
  6. say, multiply 58 with 74051161 and simulate a 32-bit processor, you’d do something
  7. like this
  8. (mod (* 58 74051161) (expt 2 32))
复制代码
报纸
ReneeBK(未真实交易用户) 发表于 2016-8-14 22:51:10
  1. 4-4. Switching Bases
  2. Problem
  3. You want to input or output binary, octal, or hexadecimal numbers. (Or actually
  4. numbers in any base from 2 up to 36.)
  5. Solution
  6. For input, use the sharpsign (#) notation;19 for output, use FORMAT. Try this:
  7. (list (list #b101010 #o52 #x2A)
  8. (loop for fmt in ’("~B" "~O" "~X")
  9. collect (format nil fmt 42)))
复制代码
地板
albertwishedu(未真实交易用户) 发表于 2016-8-15 09:00:40

7楼
franky_sas(未真实交易用户) 发表于 2016-12-20 12:06:25

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