proc nlin data=work.data;
parms a=0 to 100 by 0.1 b1=0 to 1 by 0.0001 b2=0 b3=0 b4=0;
model y=a*log(1+b1*v1+b2*v2+b3*v3+b4*v4);
run;
得出a,b1,b2,b3,b4的值,还有模型的显著性检验,可我怎么知道拟合优度呢?还是不需要知道?附结果:
Estimation Summary
Method
Gauss-Newton
Iterations
5
Subiterations
1
Average Subiterations
0.2
R
5.001E-8
PPC(b4)
1.635E-8
RPC(b4)
3.094E-6
Object
2.16E-10
Objective
2.784262
Observations Read
20
Observations Used
20
Observations Missing
0
Source
DF
Sum of Squares
Mean Square
F Value
Approx
Pr > F
Model
5
219026
43805.2
235997
<.0001
Error
15
2.7843
0.1856
Uncorrected Total
20
219029
Parameter
Estimate
Approx
Std Error
Approximate 95% Confidence
Limits
a
125.3
5.4655
113.7
137.0
b1
0.00956
0.000726
0.00801
0.0111
b2
0.00157
0.000411
0.000698
0.00245
b3
0.4848
0.0459
0.3870
0.5826
b4
0.000295
0.000037
0.000217
0.000373