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我用的是lingo9.0算的，现实结果错误，错误代号是1017.请问哪位大虾帮帮忙，因为，本人是菜鸟，所以很多东西都不懂，只能够用这个死方法。请帮帮忙。有输出结果，送20论坛币，谢谢
下面是目标函数和约束条件：


min=(G(2011)-G1(2011))^2+(G(2012)-G1(2012))^2+(G(2013)-G1(2013))^2+(G(2014)-G1(2014))^2+(G(2015)-G1(2015))^2;

G(2010)=41425;
G1(2011)=41080;
G1(2012)=48060;
G1(2013)=56240;
G1(2014)=65800;
G1(2015)=76980;
G(2015)>=65800;
G(2011)=G(2010)*(1+i(2010));
G(2012)=G(2011)*(1+i(2011));
G(2013)=G(2012)*(1+i(2012));
G(2014)=G(2013)*(1+i(2013));
G(2015)=G(2014)*(1+i(2014));
9%<=i(2010);
i(2010)<=11%;
9%<=i(2011);
i(2011)<=11%;
9%<=i(2012);
i(2012)<=11%;
9%<=i(2013);
i(2013)<=11%;
9%<=i(2014);
i(2014)<=11%;
Q(2010)/G(2010)*(1-j(2011))=Q(2011)/G(2011);
Q(2011)/G(2011)*(1-j(2012))=Q(2012)/G(2012);
Q(2012)/G(2012)*(1-j(2013))=Q(2013)/G(2013);
Q(2013)/G(2013)*(1-j(2014))=Q(2014)/G(2014);
Q(2014)/G(2014)*(1-j(2015))=Q(2015)/G(2015);
(1-j(2011)*(1-j(2012))*(1-j(2013*))*(1-j(2014*))*(1-j(2015))<=1-19%;
0.0289<=j(2011);
j(2011)<=0.0489;
0.0289<=j(2012);
j(2012)<=0.0489;
0.0289<=j(2013);
j(2013)<=0.0489;
0.0289<=j(2014);
j(2014)<=0.0489;
0.0289<=j(2015);
j(2015)<=0.0489;
((Q(2010)*k1(2010)*0.7329)+(Q(2010)*k2(2010)*0.5574)+(Q(2010)*k3(2010)*0.4226))/G(2010)*(1+l(2010))=((Q(2011)*k1(2011)*0.7329)+(Q(2011)*k2(2011)*0.5574)+(Q(2010)*k3(2011)*0.4226))/G(2011);
((Q(2011)*k1(2011)*0.7329)+(Q(2011)*k2(2011)*0.5574)+(Q(2011)*k3(2011)*0.4226))/G(2011)*(1+l(2011))=((Q(2012)*k1(2012)*0.7329)+(Q(2012)*k2(2012)*0.5574)+(Q(2012)*k3(2012)*0.4226))/G(2012);
((Q(2012)*k1(2012)*0.7329)+(Q(2012)*k2(2012)*0.5574)+(Q(2012)*k3(2012)*0.4226))/G(2012)*(1+l(2012))=((Q(2013)*k1(2013)*0.7329)+(Q(2013)*k2(2013)*0.5574)+(Q(2013)*k3(2013)*0.4226))/G(2013);
((Q(2013)*k1(2013)*0.7329)+(Q(2013)*k2(2013)*0.5574)+(Q(2013)*k3(2013)*0.4226))/G(2013)*(1+l(2013))=((Q(2014)*k1(2014)*0.7329)+(Q(2014)*k2(2014)*0.5574)+(Q(2014)*k3(2014)*0.4226))/G(2014);
((Q(2014)*k1(2014)*0.7329)+(Q(2014)*k2(2014)*0.5574)+(Q(2014)*k3(2014)*0.4226))/G(2014)*(1+l(2014))=((Q(2015)*k1(2015)*0.7329)+(Q(2015)*k2(2015)*0.5574)+(Q(2015)*k3(2015)*0.4226))/G(2015);
(1-l(2011)*(1-l(2012))*(1-l(2013*))*(1-l(2014*))*(1-l(2015))<=1-19%;
0.0313<=l(2010);
l(2010)<=0.0513;
0.0313<=l(2011);
l(2011)<=0.0513;
0.0313<=l(2012);
l(2012)<=0.0513;
0.0313<=l(2013);
l(2013)<=0.0513;
0.0313<=l(2014);
l(2014)<=0.0513;
0.0313<=l(2015);
l(2015)<=0.0513;
k1(2010)+k2(2010)+k3(2010)+k4(2010)=1;
k1(2011)+k2(2011)+k3(2011)+k4(2011)=1;
k1(2012)+k2(2012)+k3(2012)+k4(2012)=1;
k1(2013)+k2(2013)+k3(2013)+k4(2013)=1;
k1(2014)+k2(2014)+k3(2014)+k4(2014)=1;
k1(2015)+k2(2015)+k3(2015)+k4(2015)=1;

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关键词：lingo 线性规划 规划问题 Lin ING 2011 2014

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    楼主若给出模型数学表达式，这样就很容易编写了。