Jhansen cointegration test 后出现了这种情况怎么解释

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Date: 08/14/13   Time:  16:02
Sample (adjusted): 1/08/1997 7/30/2013
Included observations: 4320 after adjustments
Trend assumption: No deterministic trend (restricted constant)
Series: LNNZDS(1) LNNZDF
Lags interval (in first differences): 1 to 4
Unrestricted Cointegration Rank Test (Trace)
Hypothesized		Trace	0.05
No. of CE(s)	Eigenvalue	Statistic	Critical Value	Prob.**
None	0.003654	17.10097	20.26184	0.1288
At most 1	0.000298	1.286564	9.164546	0.9098
Trace test indicates no cointegration at the 0.05 level
* denotes rejection of the hypothesis at the 0.05 level
**MacKinnon-Haug-Michelis  (1999) p-values
Unrestricted Cointegration Rank Test (Maximum Eigenvalue)
Hypothesized		Max-Eigen	0.05
No. of CE(s)	Eigenvalue	Statistic	Critical Value	Prob.**
None	0.003654	15.81441	15.89210	0.0514
At most 1	0.000298	1.286564	9.164546	0.9098
Max-eigenvalue test indicates no cointegration at the 0.05  level
* denotes rejection of the hypothesis at the 0.05 level
**MacKinnon-Haug-Michelis  (1999) p-values
Unrestricted Cointegrating Coefficients (normalized by  b'*S11*b=I):
LNNZDS(1)	LNNZDF	C
768.4460	-770.4751	2.661557
30.73446	-26.08140	-1.947799
Unrestricted Adjustment Coefficients (alpha):
D(LNNZDS(1))	0.000105	-0.000144
D(LNNZDF)	2.16E-05	1.27E-06
1 Cointegrating Equation(s):		Log likelihood	42534.94
Normalized cointegrating coefficients (standard error in  parentheses)
LNNZDS(1)	LNNZDF	C
1.000000	-1.002640	0.003464
	(0.00158)	(0.00082)
Adjustment coefficients (standard error in parentheses)
D(LNNZDS(1))	0.080619
	(0.09974)
D(LNNZDF)	0.016583
	(0.00426)

0个cointegration 不能拒绝，一个也不能拒绝。还有种情况是两个都拒绝的，请帮忙解答下这种情况要怎么办？THX

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关键词：Integration Jhansen ration Hansen ratio restricted adjusted Series