求助如何得到这个算法

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An electronic fuse is produced by five production lines in a manufacturing operation.
The fuses are costly, are quite reliable, and are shipped to suppliers in 100-unit lots.
Because testing is destructive, most buyers of the fuses test only a small number of
fuses before deciding to accept or reject lots of incoming fuses.
All five production lines produce fuses at the same rate and normally produce
only 2% defective fuses, which are dispersed randomly in the output. Unfortunately,
production line 1 suffered mechanical difficulty and produced 5% defectives during
the month of March. This situation became known to the manufacturer after the fuses
had been shipped.Acustomer received a lot produced in March and tested three fuses.
One failed. What is the probability that the lot was produced on line 1? What is the
probability that the lot came from one of the four other lines?
Solution Let B denote the event that a fuse was drawn from line 1 and let A denote the event
that a fuse was defective. Then it follows directly that P(B) = 0.2 and P(A|B) = 3(.05)(.95)^2 = .135375.

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关键词：Manufacturer Probability Destructive MANUFACTURE production electronic suppliers produced testing number

Regarding to Question 1, the probability that the lot was produced on line 1 is P(B)=0.2 since there are 5 production lines in total and the probability of choosing any production line is simply 1/5, i.e. 0.2.

For the conditional probability P(A|B), which means the probability of A given B occurs, in this case, it means the probability of a fuse was defective given the fuse was drawn from production line 1. Thus, according to the information given, the probability of a fuse was defective is 5%. Since there were three fuses in the lot, and the other two fuses passed the test, so the probability of that is 95%*95%. Therefore, the probability of having one defective fuse and two good fuses is 5%*95%*95%. Since the defective fuse could be any one of these three fuses, so we multiplied the aforementioned probability by 3 to indicate the three senarios (or you can say three orders).

Hopefully this helps XD

thanks