对限定条件的变量计数（附数据）

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我想按家庭编码hhcode对h01_1 h01_2 h01_3 h01_4这四个变量进行计数，条件是这四个变量为1或2，求命令；
下面的person是家庭成员的代码

• * Example generated by -dataex-. To install: ssc install dataex
• clear
• input str14 hhcode float person byte(h01_1 h01_2) int h01_3 byte h01_4
• "1101010208302" 1 2 2 . .
• "1101013407301" 1 3 3 3 2
• "1101013407301" 2 3 3 3 2
• "1101013800501" 1 3 1 3 3
• "1101013800501" 2 3 1 3 3
• "1101013800501" 3 3 1 3 3
• "1101013800501" 4 3 1 3 3
• "1101013802401" 1 2 2 2 3
• "1101013802401" 2 2 2 2 3
• "1101013804101" 1 1 1 . .
• "1101013804101" 2 1 1 . .
• "1101013804101" 3 1 1 . .
• "1101013805801" 1 3 3 3 3
• "1101013805801" 2 3 3 3 3
• "1101013807901" 1 3 2 2 2
• "1101013807901" 2 3 2 2 2
• "1101013807901" 3 3 2 2 2
• "1101020921601" 1 2 3 3 3
• "1101020921601" 2 2 3 3 3
• "1101020921601" 3 2 3 3 3
• "1101021300901" 1 3 2 3 3
• "1101021300901" 2 3 2 3 3
• "1101021300901" 3 3 2 3 3
• "1101021312401" 1 2 2 2 2
• "1101021312401" 2 2 2 2 2
• "1101021312401" 3 2 2 2 2
• "1101021312401" 4 2 2 2 2
• "1101022507601" 1 2 2 2 2
• "1101022507601" 2 2 2 2 2
• "1101060900301" 1 2 2 2 2
• "1101060900301" 2 2 2 2 2
• "1101060900301" 3 2 2 2 2
• "1101060900302" 1 2 2 2 2
• "1101060900302" 2 2 2 2 2
• "1101060900302" 3 2 2 2 2
• "1101060906701" 1 2 2 2 2
• "1101060906701" 2 2 2 2 2
• "1101060911501" 1 2 2 . .
• "1101060911501" 2 2 2 . .
• "1101060911501" 3 2 2 . .
• "1101061106002" 1 2 2 2 2
• "1101061106002" 2 2 2 2 2
• "1101063511502" 1 3 3 3 3
• "1101063511502" 2 3 3 3 3
• "1101064702001" 1 2 2 2 2
• "1101064702001" 2 2 2 2 2
• "1101064702001" 3 2 2 2 2
• "1101120400102" 1 2 2 . .
• "1101120406301" 1 2 3 3 2
• "1101120406301" 2 2 3 3 2
• "1101121011101" 1 2 2 2 2
• "1101121011101" 2 2 2 2 2
• "1101121011101" 3 2 2 2 2
• "1101121011101" 4 2 2 2 2
• "1101122407901" 1 2 2 2 2
• "1101122407901" 2 2 2 2 2
• "1101122407901" 3 2 2 2 2
• "1101123713002" 1 2 3 2 2
• "1101123713002" 2 2 3 2 2
• "1101123713002" 3 2 3 2 2
• "1101123713002" 4 2 3 2 2
• "1101124309301" 1 3 3 2 3
• "1101124309301" 2 3 3 2 3
• "1101126300801" 1 2 2 2 2
• "1101126300801" 2 2 2 2 2
• "1101126300801" 3 2 2 2 2
• "1101126302002" 1 3 3 . .
• "1101126302002" 2 3 3 . .
• "1101140404701" 1 3 3 3 3
• "1101140404701" 2 3 3 3 3
• "1101140404701" 3 3 3 3 3
• "1101142009801" 1 1 1 2 2
• "1101142009801" 2 1 1 2 2
• "1101142009801" 3 1 1 2 2
• "1101142009801" 4 1 1 2 2
• "1101142009801" 5 1 1 2 2
• "1101142206901" 1 2 2 2 2
• "1101142206901" 2 2 2 2 2
• "1101142206901" 3 2 2 2 2
• "1101142210701" 1 2 2 2 2
• "1101142210701" 2 2 2 2 2
• "1101142905001" 1 3 3 . .
• "1101142905001" 2 3 3 . .
• "1101142905001" 3 3 3 . .
• "1101142911701" 1 3 2 2 3
• "1101142911701" 2 3 2 2 3
• "1101142911701" 3 3 2 2 3
• "1101142911701" 4 3 2 2 3
• "1101143908501" 1 3 2 2 2
• "1101143908501" 2 3 2 2 2
• "1101143908501" 3 3 2 2 2
• "1101145500301" 1 . . . .
• "1101145500301" 2 . . . .
• "1101145500301" 3 . . . .
• "1101145500301" 4 . . . .
• "1101145901901" 1 2 3 2 2
• "1101145901901" 2 2 3 2 2
• "1101145902701" 1 3 2 2 2
• "1101145902701" 2 3 2 2 2
• "1101145904801" 1 2 2 . .
• end
  

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这个问题好像回答过了。

黃河泉 发表于 2018-6-3 15:34
这个问题好像回答过了。

对的 ，我以为帖子沉了早上又发了一次