楼主: 高晓枫
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[问答] 哪位大大帮我解读下这个Johansen检验结果 [推广有奖]

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高晓枫 发表于 2010-4-21 20:26:31 |AI写论文

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Date: 04/21/10   Time: 20:23   
Sample (adjusted): 6 1132   
Included observations: 1127 after adjustments   
Trend assumption: Linear deterministic trend   
Series: RMBPUSD STOCKA     
Lags interval (in first differences): 1 to 4   
   
Unrestricted Cointegration Rank Test (Trace)   
   
Hypothesized  Trace 0.05
No. of CE(s) Eigenvalue Statistic Critical Value Prob.**
   
None *  0.032647  40.77061  15.49471  0.0000
At most 1  0.002980  3.363834  3.841466  0.0666
   
Trace test indicates 1 cointegrating eqn(s) at the 0.05 level   
* denotes rejection of the hypothesis at the 0.05 level   
**MacKinnon-Haug-Michelis (1999) p-values   
   
Unrestricted Cointegration Rank Test (Maximum Eigenvalue)   
   
Hypothesized  Max-Eigen 0.05
No. of CE(s) Eigenvalue Statistic Critical Value Prob.**
   
None *  0.032647  37.40677  14.26460  0.0000
At most 1  0.002980  3.363834  3.841466  0.0666
   
Max-eigenvalue test indicates 1 cointegrating eqn(s) at the 0.05 level   
* denotes rejection of the hypothesis at the 0.05 level   
**MacKinnon-Haug-Michelis (1999) p-values   
   
Unrestricted Cointegrating Coefficients (normalized by b'*S11*b=I):     
   
RMBPUSD STOCKA   
1.280444  0.000841   
1.699661 -0.000223   
   
   
Unrestricted Adjustment Coefficients (alpha):     
   
D(RMBPUSD) -0.001040  1.47E-05  
D(STOCKA)  1.237318  3.749471  
   
   
1 Cointegrating Equation(s):   Log likelihood -2138.558
   
Normalized cointegrating coefficients (standard error in parentheses)   
RMBPUSD STOCKA   
1.000000  0.000657   
  (0.00010)   
   
Adjustment coefficients (standard error in parentheses)   
D(RMBPUSD) -0.001331   
  (0.00022)   
D(STOCKA)  1.584316   
  (2.64394)
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关键词:johansen检验 Johansen johans Hansen ans 检验 结果 Johansen 解读

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backsss 发表于3楼  查看完整内容

seems like depends on both test shown on ur output, the estimated cointegrating vectors should be 1 (Trace and UCR Test). Then take a look at output where "1 cointe..." shown ur coefficient of stocka which is its beta. Also the 1st diff of your parameters. Numbers in brackets are t-sta.

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沙发
高晓枫 发表于 2010-4-21 20:32:23
用E-G作了下 残差不平稳 考虑到E-G局限性作了下Johansen检验。。。却一时翻不到相关E-VIEWS结果的说明相关资料。。只能厚脸皮上来发帖问了

藤椅
backsss 发表于 2010-4-21 23:16:29
seems like depends on both test shown on ur output, the estimated cointegrating vectors should be 1 (Trace and UCR Test). Then take a look at output where "1 cointe..." shown ur coefficient of stocka which is its beta. Also the 1st diff of your parameters. Numbers in brackets are t-sta.
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