latex 公式换行

公式可以输入，但太长，从第一个“+”号那里想挪到第二行，想得到如下所表示的公式：

编译命令如下，也可以换行，但是就不会让那个“+”号和“=”那里对齐，编译出来时这样子，


有哪位知 道应该在哪里做修改？
\[\begin{array}{l}
\left[ \begin{array}{l}
{h_{11,t}}\\
{h_{21,t}}
\end{array} \right.\left. \begin{array}{l}
{h_{12,t}}\\
{h_{22,t}}
\end{array} \right]=
\left[ \begin{array}{l}
{a_{11}}\\
{a_{21}}
\end{array} \right.{\left. \begin{array}{l}
{a_{12}}\\
{a_{22}}
\end{array} \right]^ \mathrm{ T }}\left[ \begin{array}{l}
{\varepsilon ^2}_{1,t - 1}\\
{\varepsilon _{2,t - 1}}{\varepsilon _{1,t - 1}}
\end{array} \right.\left. \begin{array}{l}
{\varepsilon _{1,t - 1}}{\varepsilon _{2,t - 1}}\\
{\varepsilon ^2}_{2,t - 1}
\end{array} \right]\left[ \begin{array}{l}
{a_{11}}\\
{a_{21}}
\end{array} \right.\left. \begin{array}{l}
{a_{12}}\\
{a_{22}}
\end{array} \right]\\
{\rm{                                }} + \left[ \begin{array}{l}
{b_{11}}\\
{b_{21}}
\end{array} \right.{\left. \begin{array}{l}
{b_{12}}\\
{b_{22}}
\end{array} \right]^ \mathrm{ T }}\left[ \begin{array}{l}
{h_{11,t - 1}}\\
{h_{21,t - 1}}
\end{array} \right.\left. \begin{array}{l}
{h_{12,t - 1}}\\
{h_{22,t - 1}}
\end{array} \right]\left[ \begin{array}{l}
{b_{11}}\\
{b_{21}}
\end{array} \right.\left. \begin{array}{l}
{b_{12}}\\
{b_{22}}
\end{array} \right] + \left[ \begin{array}{l}
{c_{11}}\\
{c_{21}}
\end{array} \right.{\left. \begin{array}{l}
{c_{12}}\\
{c_{22}}
\end{array} \right]^ \mathrm{ T }}\left[ \begin{array}{l}
{c_{11}}\\
{c_{21}}
\end{array} \right.\left. \begin{array}{l}
{c_{12}}\\
{c_{22}}
\end{array} \right]{\rm{ }}
\end{array}\]

记错了，是\newline

在加号前面加个\linebreak

floydgyf 发表于 2012-4-2 22:21
在加号前面加个\linebreak

还是那样，没啥变化啊，但还是非常感谢

或者\linebreak[4]

floydgyf 发表于 2012-4-2 22:30
记错了，是\newline

查了一下，这两个都是用于换行的，我现在已换行，就是没法对齐，您还有别的编译命令吗？

再用个\begin{align}
\end{align}

中间用&对齐
不要编号的公式用\nonumber

floydgyf 发表于 2012-4-2 22:49
再用个\begin{align}
\end{align}

非常感谢，我试试！