Stata怎么进行数据分半？ 求助。。

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我有一个900多case的Stata数据，想用其中的一半来做探索性因素分析，另一半做验证性因素分析。
用sample命令的时候，只能保留一半，另一半则被删除了

请问，我想将数据分半，随机的分成2份，2份做不同的分析。  这个随机分半的过程怎么实现？

谢谢！

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关键词：Stata tata STATA数据 验证性因素分析 探索性因素分析 大侠

set seed 12345
gen random=runiform()
sort random
gen validation=_n<=450            //assume you sample size is 900
label define valid 1 "model_build" 0 "model_valid"
label val validation valid

hplcdadong 发表于 2013-3-21 21:05
set seed 12345
gen random=runiform()
sort random

感谢楼上！

我摸索了一个这样的
set obs 900
gen x=rnormal()
xtile x2=x, n(2)
然后导出数据到Mplus，加入一条if x2==1，或者if  x2==2

这样子可以吗？这样是随机分半了吗？

ps：怎么样将数据split成两个stata数据文件？

help bsample

Your method may be Ok but it's not a standard procedure, especially the use of "rnormal()".  Personally I have never seen Stata experts use "rnormal()" instead of "runiform()" for the aim of random sampling.

As regards to splitting the Stata file, there are several methods, the simplest one is to find and install the command "savesome"

Good luck

hplcdadong 发表于 2013-3-22 10:28
Your method may be Ok but it's not a standard procedure, especially the use of "rnormal()".  Persona ...

如果我在上面原有的语句里面，用runiform()替换rnormal(),这样做没问题吧？
谢谢！

It should work for this case. But "xtile" can not handle complicated requirements. Actually there is a lit bit more simple way for your case

set seed 12345
gen random=runiform()
sort random
gen validation=group(2)            //any sample split half

hplcdadong 发表于 2013-3-23 20:23
It should work for this case. But "xtile" can not handle complicated requirements. Actually there is ...

Thanks a lot

直接复制，干嘛纠结，命令