EVIEWS协整方程？

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Hypothesized		Trace	5 Percent	1 Percent
No. of CE(s)	Eigenvalue	Statistic	Critical Value	Critical Value
None *	0.033499	19.89849	15.41	20.04
At most 1	0.005628	2.827760	3.76	6.65
Trace test indicates 1 cointegrating equation(s) at the 5% level
Trace test indicates no cointegration at the 1% level
*(**) denotes rejection of the hypothesis at the 5%(1%) level
Hypothesized		Max-Eigen	5 Percent	1 Percent
No. of CE(s)	Eigenvalue	Statistic	Critical Value	Critical Value
None *	0.033499	17.07073	14.07	18.63
At most 1	0.005628	2.827760	3.76	6.65
Max-eigenvalue test indicates 1 cointegrating equation(s) at the 5% level
Max-eigenvalue test indicates no cointegration at the 1% level
*(**) denotes rejection of the hypothesis at the 5%(1%) level
Unrestricted Cointegrating Coefficients (normalized by b'*S11*b=I):
RMBPUSD	STOCKA
-0.158528	-0.001534
-0.154265	-0.002499
Unrestricted Adjustment Coefficients (alpha):
D(RMBPUSD)	-0.048794	0.037028
D(STOCKA)	9.662281	1.765617
1 Cointegrating Equation(s):		Log likelihood	-3154.712
Normalized cointegrating coefficients (standard error in parentheses)
RMBPUSD	STOCKA
1.000000	0.009675
	(0.00110)
Adjustment coefficients (standard error in parentheses)
D(RMBPUSD)	0.007735
	(0.00400)
D(STOCKA)	-1.531740
	(0.40769)

请问：这个结果的协整方程如何得出？

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关键词：EVIEWS Views Eview view 协整方程 EVIEWS 方程

 

Hypothesized		Trace	5 Percent	1 Percent
No. of CE(s)	Eigenvalue	Statistic	Critical Value	Critical Value
None *	0.023583	16.36175	15.41	20.04
At most 1 *	0.008754	4.404927	3.76	6.65
Trace test indicates 2 cointegrating equation(s) at the 5% level
Trace test indicates no cointegration at the 1% level
*(**) denotes rejection of the hypothesis at the 5%(1%) level
Hypothesized		Max-Eigen	5 Percent	1 Percent
No. of CE(s)	Eigenvalue	Statistic	Critical Value	Critical Value
None	0.023583	11.95682	14.07	18.63
At most 1 *	0.008754	4.404927	3.76	6.65
Max-eigenvalue test indicates no cointegration at both 5% and 1% levels
*(**) denotes rejection of the hypothesis at the 5%(1%) level
Unrestricted Cointegrating Coefficients (normalized by b'*S11*b=I):
RMBPUSD	STOCKB
0.167170	0.028192
-0.055285	-0.020450
Unrestricted Adjustment Coefficients (alpha):
D(RMBPUSD)	0.041099	0.046015
D(STOCKB)	-0.728759	0.203484
1 Cointegrating Equation(s):		Log likelihood	-1951.965
Normalized cointegrating coefficients (standard error in parentheses)
RMBPUSD	STOCKB
1.000000	0.168640
	(0.01835)
Adjustment coefficients (standard error in parentheses)
D(RMBPUSD)	0.006870
	(0.00421)
D(STOCKB)	-0.121826
	(0.03900)

这个结果说明有两个协整方程吧？那么协整方程如何得出呢？

只看出一个协整方程，这个分析结果得不到协整方程，要另外操作

怎么看呀？

晕呀，谁能快点帮忙解决一下

同问，怎么得出协整方程？