.stack a b c d,into(x) clear
.rename _stack treat
.egen id=seq(),t(8)
.sort id treat
.genrank rankx=x
.anova rankx id treat
Number of obs = 32 R-squared = 0.8207
Root MSE = 4.81905 Adj R-squared = 0.7353
Source | Partial SS df MS F Prob > F
-----------+----------------------------------------------------
Model | 2231.8125 10 223.18125 9.61 0.0000
|
id | 1473.75 7 210.535714 9.07 0.0000
treat | 758.0625 3 252.6875 10.88 0.0002
|
Residual | 487.6875 21 23.2232143
-----------+----------------------------------------------------
Total | 2719.5 31 87.7258065
.test _b[treat[1]]=_b[treat[2]]
输到最后的时候总显示
invalid syntax
r(198);
请问是什么问题??求回复,毕业论文用,谢谢!!!