检验命令:
xtreg roe m rd2 size lev gri rc s1 s2 ct,fe(rd2、m均显著)
est store fe
xtivreg roe m size lev gri rc s1 s2 ct (rd2=rdt),fe(核心解释变量是rd2,m是中介变量,其他是控制变量,此时rd2不显著)
est store feiv
hausman fe feiv
豪斯曼内生性检验结果:
hausman fe feiv
---- Coefficients ----
| (b) (B) (b-B) sqrt(diag(V_b-V_B))
| fe feiv Difference S.E.
-------------+----------------------------------------------------------------
m | 10.05123 10.06492 -.0136964 .
rd2 | .0038656 -.0210177 .0248833 .
size | .1148817 .0981709 .0167108 .
lev | -.9222642 -.9299148 .0076506 .
gri | .0091528 .0115147 -.0023619 .
rc | .0987147 .0797515 .0189632 .
s1 | 1.118682 1.087517 .0311647 .
s2 | -.0051087 -.0085658 .0034571 .
ct | .1618934 .1646754 -.002782 .
------------------------------------------------------------------------------
b = consistent under Ho and Ha; obtained from xtreg
B = inconsistent under Ha, efficient under Ho; obtained from xtivreg
Test: Ho: difference in coefficients not systematic
chi2(9) = (b-B)'[(V_b-V_B)^(-1)](b-B)
= -0.99 chi2<0 ==> model fitted on these
data fails to meet the asymptotic
assumptions of the Hausman test;
see suest for a generalized test
(stata小白,非常感谢指导)
ZY一 发表于 2020-2-7 15:17
检验命令:
xtreg roe m rd2 size lev gri rc s1 s2 ct,fe(rd2、m均显著)
est store fe
没有看过你的具体数据,不是很清楚原因。不过你可以试试以下代码,看看能不能解决问题:
xtreg roe m rd2 size lev gri rc s1 s2 ct, fe;
est store fe;
xtivreg roe m size lev gri rc s1 s2 ct (rd2 = rdt), fe;
est store feiv;
hausman feiv fe, constant sigmamore.
不过我个人还是认为不要用豪斯曼检验,这个检验只能适用于普通标准误。