Suppose X is an n × K matrix with full column rank of K. Show that
X的转秩乘以X is nonsigular (invertible).
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回帖推荐sherman_shi 发表于2楼 查看完整内容 Suppose A is an n × K matrix with full column rank of K. Show that
A'A (K×K) is nonsigular (invertible), which means Rank(A'A)=Rank(A)=K.
Prove equality of their null spaces. Null space of the A'A matrix is given by vectors x for which A'Ax=0. If this condition is fulfilled, also holds 0=x'A'Ax=0, which means Ax=0.
On the other hand, if Ax=0, then A'Ax=0.
So, their null spaces are same ...
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