【求助】用tobit运算后显示R2为负值，不知该如何解释？

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以下是程序运行后显示的：

LR chi2(9)=34.82    Prob > chi2=0.0001

Log likelihood =30.79076    Pseudo R2=-1.3011

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关键词：Tobit bit Likelihood pseudo like 如何 程序

http://www.stata.com/support/faqs/statistics/pseudo-r2/

想知道结果

Concerning the pseudo-R2, we use the formula

        pseudo-R2 = 1 − L1/L0
where L0 and L1 are the constant-only and full model log-likelihoods, respectively.

For discrete distributions, the log likelihood is the log of a probability, so it is always negative (or zero). Thus 0 ≥ L1 ≥ L0, and so 0 ≤ L1/L0 ≤ 1, and so 0 ≤ pseudo-R2 ≤1 for DISCRETE distributions.

For continuous distributions, the log likelihood is the log of a density. Since density functions can be greater than 1 (cf. the normal density at 0), the log likelihood can be positive or negative. Similarly, mixed continuous/discrete likelihoods like tobit can also have a positive log likelihood.

If L1 > 0 and L0 < 0, then L1/L0 < 0, and 1 − L1/L0 > 1.

If L1 > L0 > 0 and then L1/L0 > 1, and 1 − L1/L0 < 0.

Hence, this formula for pseudo-R2 can give answers > 1 or < 0 for continuous or mixed continuous/discrete likelihoods like tobit.