[求助]请各位高手指点一下问题在哪里

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数据请见附件。
我的目的是要计算第一列与其它各列的差异，请问应如何作统计分析？

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关键词：高手指点 统计分析 计分析 求助 高手 指点

经正态分布检测（shapiro.test），只有第二列和第六列数据不符正态分布。因而用t检验不合适，但用wilcox.test检测了一下，但出现了警告信息”In wilcox.test.default(A, B[, 1]) : cannot compute exact p-value with ties“，不知道相应的结果还对不对，请高手指正！

> wilcox.test(A,B[,1])

        Wilcoxon rank sum test with continuity correction

data:  A and B[, 1]
W = 49, p-value = 0.00184
alternative hypothesis: true location shift is not equal to 0

Warning message:
In wilcox.test.default(A, B[, 1]) : cannot compute exact p-value with ties
> wilcox.test(A,B[,2])

        Wilcoxon rank sum test with continuity correction

data:  A and B[, 2]
W = 49, p-value = 0.002045
alternative hypothesis: true location shift is not equal to 0

Warning message:
In wilcox.test.default(A, B[, 2]) : cannot compute exact p-value with ties
> wilcox.test(A,B[,3])

        Wilcoxon rank sum test with continuity correction

data:  A and B[, 3]
W = 49, p-value = 0.002045
alternative hypothesis: true location shift is not equal to 0

Warning message:
In wilcox.test.default(A, B[, 3]) : cannot compute exact p-value with ties
> wilcox.test(A,B[,4])

        Wilcoxon rank sum test with continuity correction

data:  A and B[, 4]
W = 49, p-value = 0.002045
alternative hypothesis: true location shift is not equal to 0

Warning message:
In wilcox.test.default(A, B[, 4]) : cannot compute exact p-value with ties
> wilcox.test(A,B[,5])

        Wilcoxon rank sum test with continuity correction

data:  A and B[, 5]
W = 49, p-value = 0.00184
alternative hypothesis: true location shift is not equal to 0

Warning message:
In wilcox.test.default(A, B[, 5]) : cannot compute exact p-value with ties

经正态分布检测（shapiro.test），只有第二列和第六列数据不符正态分布。因而用t检验不合适，但用wilcox.test检测了一下，但出现了警告信息”In wilcox.test.default(A, B[, 1]) : cannot compute exact p-value with ties“，不知道相应的结果还对不对，请高手指正！（A为数据的第一列, B 1-5为数据的第2-6列）

> wilcox.test(A,B[,1])

        Wilcoxon rank sum test with continuity correction

data:  A and B[, 1]
W = 49, p-value = 0.00184
alternative hypothesis: true location shift is not equal to 0

Warning message:
In wilcox.test.default(A, B[, 1]) : cannot compute exact p-value with ties
> wilcox.test(A,B[,2])

        Wilcoxon rank sum test with continuity correction

data:  A and B[, 2]
W = 49, p-value = 0.002045
alternative hypothesis: true location shift is not equal to 0

Warning message:
In wilcox.test.default(A, B[, 2]) : cannot compute exact p-value with ties
> wilcox.test(A,B[,3])

        Wilcoxon rank sum test with continuity correction

data:  A and B[, 3]
W = 49, p-value = 0.002045
alternative hypothesis: true location shift is not equal to 0

Warning message:
In wilcox.test.default(A, B[, 3]) : cannot compute exact p-value with ties
> wilcox.test(A,B[,4])

        Wilcoxon rank sum test with continuity correction

data:  A and B[, 4]
W = 49, p-value = 0.002045
alternative hypothesis: true location shift is not equal to 0

Warning message:
In wilcox.test.default(A, B[, 4]) : cannot compute exact p-value with ties
> wilcox.test(A,B[,5])

        Wilcoxon rank sum test with continuity correction

data:  A and B[, 5]
W = 49, p-value = 0.00184
alternative hypothesis: true location shift is not equal to 0

Warning message:
In wilcox.test.default(A, B[, 5]) : cannot compute exact p-value with ties

是用wilcox.test还是用kruskal.test呢？

经正态分布检测（shapiro.test），只有第二列和第六列数据不符正态分布。因而用t检验不合适，但用wilcox.test检测了一下，但出现了警告信息”In wilcox.test.default(A, B[, 1]) : cannot compute exact p-value with ties“，不知道相应的结果还对不对，请高手指正！（A为数据的第一列, B 1-5为数据的第2-6列）

不知道怎么搞的，提交了几次都没返回结果页面，然后返回，却造成重复，请版主见谅！

请各位指点，谢谢~！

只好再顶！