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(11) thatb(tl; = C ) =tn;tl(; = C ) = b(tl; = ) =tn;tl(; = ) 对于n+1 l N: (37)然后,对于Xtn=C x、 我们得到B(tl; = C ) hC公司 x个 (1 dtK)l镍tn;tl(; = C )=b(tl; = ) hx公司 (1 dtK)l镍tn;tl(; = )= tn;tl(x; = ) :因此tn;tl(x; = ) = tn;tl(C x; = C ) :3、根据性质1和2,我们得到^Btn;ti(x);tn;ti; = = F^Btn;ti(C x) ;tn;ti; = C ;andF公司(Btn;ti(x);tn;ti; = ) = F级(Btn;ti(C x) ;tn;ti; = C ) ,对于tn+1 ti公司 tN:然后,根据公式(16),Ptn;ti(x; = ) = Ptn;ti(C x; = C ) :4、根据性质1 3和等式。(17) (23),我们得到了(Ztn;ti(x)jtn(x)>ti; = ) = E(Ztn;ti(C x) jtn(C x) >ti; = C ) ;andE(Ztn;ti(x)jtn(x)>ti1. = ) = E(Ztn;ti(C x) jtn(C x) >ti1. = C ) :然后,根据等式。(9) ,(11),(24)和(25)我们得到了 E(Xtn;ti(x)jtn(x)>ti; = ) = E(Xtn;ti(C x) jtn(C x) >ti; = C ) ;andC公司 E(Xtn;ti(x)jtn(x)>ti1. = ) = E(Xtn;ti(C x) jtn(C x) >ti1. = C ) ;这意味着根据公式(27),C Etn;ti(x; = ) = Etn;ti(C x; = C ) ;对于tn+1 ti公司 tN.5。根据性质3、4和等式(8),我们在延拓区域C中得到 VC(x;tn; = ) = CNXi=n+1Ptn;ti(x; = ) @Etn;ti(x; = ) +dt公司N1Xj=ihtj()A=NXi=n+1Ptn;ti(C x; = C ) @Etn;ti(C x; = C ) +dt公司N1Xj=ihtj(C )A.因此 VC(x;tn; = ) = VC(C x;tn; = C ) ; (38)对于hti() 这与, 对于tn+1 ti公司 tN.0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2-12-10-8-6-4-20σb(9,σ,h0,10(σ))b(7,σ,h0,10(σ))b(5,σ,h0,10(σ))b(3,σ,h0,10(σ))b(1,σ,h0,10(σ))图3:阈值函数,b(tN;; h0;t) 对于tn=1;3.5.7.9; T=10,dt=1;K=0:5;对于0:1 2.和hti= (tN ti) 101、最后,根据等式。
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