楼主: aoyunzhong2008
7049 1

[求助]xtabond2所报告的检验统计量的含义 [推广有奖]

  • 0关注
  • 0粉丝

本科生

58%

还不是VIP/贵宾

-

威望
0
论坛币
18 个
通用积分
1.2000
学术水平
0 点
热心指数
0 点
信用等级
0 点
经验
705 点
帖子
29
精华
0
在线时间
160 小时
注册时间
2007-3-20
最后登录
2024-9-5

楼主
aoyunzhong2008 发表于 2009-6-2 18:06:00 |AI写论文

+2 论坛币
k人 参与回答

经管之家送您一份

应届毕业生专属福利!

求职就业群
赵安豆老师微信:zhaoandou666

经管之家联合CDA

送您一个全额奖学金名额~ !

感谢您参与论坛问题回答

经管之家送您两个论坛币!

+2 论坛币

. xtabond2 n  nL1 nL2  w  wL1 k kL1 kL2 ys ysL1 ysL2  yr1978-yr1983,gmm( nL1) i

> v( nL2 w  wL1  k kL1 kL2 ys ysL1 ysL2 yr1978-yr1983) noleveleq nocons

Favoring speed over space. To switch, type or click on mata: mata set matafavor

>  space, perm.

Dynamic panel-data estimation, one-step difference GMM

------------------------------------------------------------------------------

Group variable: id                              Number of obs      =       611

Time variable : year                            Number of groups   =       140

Number of instruments = 41                      Obs per group: min =         4

Wald chi2(16) =   1804.32                                      avg =      4.36

Prob > chi2   =     0.000                                      max =         6

------------------------------------------------------------------------------

           n |      Coef.   Std. Err.      z    P>|z|     [95% Conf. Interval]

-------------+----------------------------------------------------------------

         nL1 |   .6862261   .1466575     4.68   0.000     .3987827    .9736696

         nL2 |  -.0853582   .0438509    -1.95   0.052    -.1713043    .0005879

           w |  -.6078208   .0649026    -9.37   0.000    -.7350275   -.4806141

         wL1 |   .3926237   .1077977     3.64   0.000     .1813441    .6039032

           k |   .3568456   .0365434     9.76   0.000     .2852219    .4284693

         kL1 |  -.0580012   .0575366    -1.01   0.313    -.1707708    .0547685

         kL2 |  -.0199475   .0410788    -0.49   0.627    -.1004604    .0605654

          ys |   .6085073   .1327679     4.58   0.000      .348287    .8687276

        ysL1 |  -.7111651   .1820286    -3.91   0.000    -1.067935   -.3543955

        ysL2 |   .1057969    .140974     0.75   0.453     -.170507    .3821008

      yr1978 |   .0077033   .0304006     0.25   0.800    -.0518808    .0672875

      yr1979 |   .0172578   .0278955     0.62   0.536    -.0374164     .071932

      yr1980 |   .0297185    .027434     1.08   0.279    -.0240511    .0834881

      yr1981 |   -.004071   .0279204    -0.15   0.884    -.0587941    .0506521

      yr1982 |  -.0193555   .0240369    -0.81   0.421     -.066467     .027756

      yr1983 |  -.0136171   .0210236    -0.65   0.517    -.0548227    .0275885

------------------------------------------------------------------------------

Instruments for first differences equation

  Standard

    D.(nL2 w wL1 k kL1 kL2 ys ysL1 ysL2 yr1978 yr1979 yr1980 yr1981 yr1982

    yr1983)

  GMM-type (missing=0, separate instruments for each period unless collapsed)

    L(1/.).nL1

------------------------------------------------------------------------------

Arellano-Bond test for AR(1) in first differences: z =  -3.99  Pr > z =  0.000

Arellano-Bond test for AR(2) in first differences: z =  -0.55  Pr > z =  0.583

------------------------------------------------------------------------------

Sargan test of overid. restrictions: chi2(25)   =  67.59  Prob > chi2 =  0.000

  (Not robust, but not weakened by many instruments.)

Difference-in-Sargan tests of exogeneity of instrument subsets:

  iv(nL2 w wL1 k kL1 kL2 ys ysL1 ysL2 yr1978 yr1979 yr1980 yr1981 yr1982 yr1983

> )

    Sargan test excluding group:     chi2(10)   =  21.16  Prob > chi2 =  0.020

    Difference (null H = exogenous): chi2(15)   =  46.43  Prob > chi2 =  0.000

.请问各位大侠

Wald chi2(16) =1804.32是不是相关零假设下渐进卡方分布估计系数的联合显著性检验?

Arellano-Bond test for AR(1) in first differences: z =  -3.99  Pr > z =  0.000

Arellano-Bond test for AR(2) in first differences: z =  -0.55  Pr > z =  0.583

分别是无序列相关下残差渐进标准正态分布的一阶自相关和二阶自相关检验吗?

Sargan test of overid. restrictions: chi2(25)   =  67.59  Prob > chi2 =  0.000

是检验工具变量正确性零假设下渐进分布孤独识别的约束检验吗?

如果不是 那这些检验统计量如何求啊! 不知道有谁知道啊?

二维码

扫码加我 拉你入群

请注明:姓名-公司-职位

以便审核进群资格,未注明则拒绝

关键词:XTABOND abond 统计量 tab abo 检验 含义 统计量 XTABOND

沙发
tlu8623 发表于 2014-2-17 15:49:17
看上去很复杂的样子,怎么没有高手解答呢

您需要登录后才可以回帖 登录 | 我要注册

本版微信群
加好友,备注jltj
拉您入交流群
GMT+8, 2025-12-9 14:51