id | name | value |
1 | jj | 12 |
1 | jj | 56 |
1 | jj | 2 |
2 | mm | 5 |
2 | mm | 3 |
2 | mm | 5 |
3 | ii | 314 |
p |
5 |
id | name | value | p |
1 | jj | 12 | 5 |
1 | jj | 56 | 5 |
1 | jj | 2 | 5 |
2 | mm | 5 | 5 |
2 | mm | 3 | 5 |
2 | mm | 5 | 5 |
3 | ii | 314 | 5 |
data a;
set a;
i=1;
run;
data b;
set b;
i=1;
data c;
merge a b;
by i;
run;
有没有更简单的方法,能够一个data步搞定的?