| id | disposition |
| 001 | complete |
| 002 | ae |
| 002 | complete |
| 002 | complete |
| 003 | complete |
| 004 | death |
| 005 | complete |
| 006 | death |
| 006 | death |
| 006 | complete |
| 007 | complete |
| 008 | sae |
| 009 | complete |
| 010 | cancel |
| 010 | complete |
| 010 | complete |
| 011 | complete |
| 012 | complete |
| 013 | ae |
| 013 | ae |
| 014 | complete |
| 015 | complete |
对,就是刚才提问的升级版,
变成need=
| id | disposition | n |
| 001 | complete | 1 |
| 002 | ae | 2 |
| 002 | complete | 2 |
| 003 | complete | 1 |
| 004 | death | 1 |
| 005 | complete | 1 |
| 006 | death | 2 |
| 006 | complete | 2 |
| 007 | complete | 1 |
| 008 | sae | 1 |
| 009 | complete | 1 |
| 010 | cancel | 2 |
| 010 | complete | 2 |
| 011 | complete | 1 |
| 012 | complete | 1 |
| 013 | ae | 1 |
| 014 | complete | 1 |
| 015 | complete | 1 |
然后我写的程序是
proc sql noprint;
create table need as select *,count(*) as n from origin where exists(select distinct * from origin) group by id ;
quit;
但是它没有去重,直接标记了!



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