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[其它] 怎么理解John Hull期权期货衍生品书中的(22.2)式? [推广有奖]

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楼主
euser2011 发表于 2011-11-18 02:09:32 |AI写论文

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John Hull期权期货衍生品书第7版的由债券价格来计算违约概率一节,(22.2)式称,

每年的平均违约密度 = 企业债券收益率与无风险收益率的利差 / (1 - 回收率期望)

想了一阵子没明白。请教这个式子应该如何来理解?当左边为0或1的时候可以理解,可为什么是一个简单的分式?
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关键词:John Hull 期权期货 John hull hul 企业债券 衍生品 收益率 回收率 如何

沙发
quanjk 发表于 2011-11-18 07:59:21
友情帮顶

藤椅
euser2011 发表于 2011-11-28 01:47:53
我现在觉得原因可能和下文的第二段一样。
http://www.economist.com/blogs/f ... n_defense_of_copula

板凳
dewscf 发表于 2017-11-27 16:29:01
我现在也在看这个,信用风险的测量,也是没弄懂他想说的违约率的公式到底是怎么来的?楼主知道了吗?知道了的话能否告诉一声

报纸
110199837 在职认证  发表于 2020-3-24 09:03:52
Loss must be covered by its yield, simple as that. The left hand side of equation 1, \lambda*(1-R) is the estimated total losses because \lambda is the frequency (called hazard rate) of default, times 1 minus recovery rate would be the total losses, and it has to be met with the potential yield should no default happen, which is the right hand side. Then by moving the 1-R to the right hand side would be your equation (22.2).

The whole thing is based on pricing principle that the market value of a bond (as well as any other assets traded in open markets) must be priced considering the default rate and recovery rate.

地板
110199837 在职认证  发表于 2020-3-24 09:09:32
Btw the hazard rate is constant when the underlying probability distribution of default incidents is exponential, in which case we can drop the \bar above the \lambda since the whole default process would be smooth, meaning the frequency, or times of default happened in any fixed time period is a constant. In this case the equation is exact, not approximation.

If the underlying distribution is not exponential we can still use the average hazard rate \lambda with \bar above it to approximate the average frequency of default. That's why the author says here "This means that it is approximately true that".

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