请教：johansen协积检验后如何得出长期方程

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以下是johansen检验结果，可以看出有至少存在两个协积向量，请问如何据此求出长期均衡方程啊

Date: 05/15/08   Time: 11:37    
Sample (adjusted): 2000:05 2007:12    
Included observations: 92 after adjustments    
Trend assumption: Linear deterministic trend    
Series: LNCON LNY LNNW LNSW     
Lags interval (in first differences): 1 to 3    
    
Unrestricted Cointegration Rank Test (Trace)    
    
Hypothesized  Trace 0.05 
No. of CE(s) Eigenvalue Statistic Critical Value Prob.**
    
None *  0.313700  74.97432  47.85613  0.0000
At most 1 *  0.307146  40.34183  29.79707  0.0021
At most 2  0.066434  6.583778  15.49471  0.6265
At most 3  0.002815  0.259382  3.841466  0.6105
    
 Trace test indicates 2 cointegrating eqn(s) at the 0.05 level    
 * denotes rejection of the hypothesis at the 0.05 level    
 **MacKinnon-Haug-Michelis (1999) p-values    
    
Unrestricted Cointegration Rank Test (Maximum Eigenvalue)    
    
Hypothesized  Max-Eigen 0.05 
No. of CE(s) Eigenvalue Statistic Critical Value Prob.**
    
None *  0.313700  34.63249  27.58434  0.0053
At most 1 *  0.307146  33.75805  21.13162  0.0005
At most 2  0.066434  6.324396  14.26460  0.5719
At most 3  0.002815  0.259382  3.841466  0.6105
    
 Max-eigenvalue test indicates 2 cointegrating eqn(s) at the 0.05 level    
 * denotes rejection of the hypothesis at the 0.05 level    
 **MacKinnon-Haug-Michelis (1999) p-values    
    
 Unrestricted Cointegrating Coefficients (normalized by b'*S11*b=I):     
    
LNCON LNY LNNW LNSW 
 42.94225 -70.88197  26.63113  4.250296 
-43.19783  17.50987  16.21206  3.018765 
-0.860124 -18.05753  19.38959  0.392902 
 11.99917  15.70944 -19.24073  1.564908 
    
    
 Unrestricted Adjustment Coefficients (alpha):     
    
D(LNCON) -0.010982  0.016138  0.004287 -0.001192
D(LNY)  0.010831  0.001594  0.004308 -0.001439
D(LNNW) -0.002772 -0.004052  0.000447 -0.000147
D(LNSW) -0.000541 -0.002281  0.014072  0.001527
    
    
1 Cointegrating Equation(s):   Log likelihood  775.1170 
    
Normalized cointegrating coefficients (standard error in parentheses)    
LNCON LNY LNNW LNSW 
 1.000000 -1.650635  0.620161  0.098977 
  (0.19690)  (0.16119)  (0.02082) 
    
Adjustment coefficients (standard error in parentheses)    
D(LNCON) -0.471587   
  (0.21156)   
D(LNY)  0.465098   
  (0.17395)   
D(LNNW) -0.119041   
  (0.04376)   
D(LNSW) -0.023237   
  (0.30080)   
    
    
2 Cointegrating Equation(s):   Log likelihood  791.9961 
    
Normalized cointegrating coefficients (standard error in parentheses)    
LNCON LNY LNNW LNSW 
 1.000000  0.000000 -0.699319 -0.124846 
   (0.02478)  (0.02265) 
 0.000000  1.000000 -0.799378 -0.135598 
   (0.02053)  (0.01877) 
    
Adjustment coefficients (standard error in parentheses)    
D(LNCON) -1.168712  1.060991  
  (0.27867)  (0.33404)  
D(LNY)  0.396251 -0.739801  
  (0.24649)  (0.29547)  
D(LNNW)  0.056013  0.125536  
  (0.05543)  (0.06644)  
D(LNSW)  0.075305 -0.001587  
  (0.42637)  (0.51109)  
    
    
3 Cointegrating Equation(s):   Log likelihood  795.1583 
    
Normalized cointegrating coefficients (standard error in parentheses)    
LNCON LNY LNNW LNSW 
 1.000000  0.000000  0.000000 -0.472319 
    (0.29675) 
 0.000000  1.000000  0.000000 -0.532788 
    (0.33802) 
 0.000000  0.000000  1.000000 -0.496874 
    (0.41767) 
    
Adjustment coefficients (standard error in parentheses)    
D(LNCON) -1.172399  0.983584  0.052287 
  (0.27713)  (0.34217)  (0.16703) 
D(LNY)  0.392546 -0.817586  0.397798 
  (0.24472)  (0.30215)  (0.14750) 
D(LNNW)  0.055629  0.117460 -0.130850 
  (0.05535)  (0.06834)  (0.03336) 
D(LNSW)  0.063201 -0.255700  0.221465 
  (0.41522)  (0.51267)  (0.25026) 
    

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关键词：Johansen johans Hansen ans coefficients 检验 方程 Johansen

我也想知道.....

   
1 Cointegrating Equation(s):   Log likelihood  775.1170
   
Normalized cointegrating coefficients (standard error in parentheses)   
LNCON LNY LNNW LNSW
1.000000 -1.650635  0.620161  0.098977
  (0.19690)  (0.16119)  (0.02082)

基本可以写作：
LNCON -1.650635LNY+0.620161LNNW+0.098977LNSW=0