SVAR模型用A B矩阵估计出来的结果怎么看呢?都是什么含义 哪个是哪个的系数啊 为什么要这么弄呢?怎么看 谢谢
SVAR模型用A B矩阵估计出来的结果怎么看呢?都是什么含义 哪个是哪个的系数啊 为什么要这么弄呢?怎么看 谢谢
Model: Ae = Bu where E[uu']=I
Restriction Type: short-run pattern matrix
A =
1 0 0 0 0 0
C(1) 1 0 0 0 0
C(2) C(6) 1 0 0 0
C(3) C(7) C(10) 1 0 0
C(4) C(8) C(11) C(13) 1 0
C(5) C(9) C(12) C(14) C(15) 1
B =
C(16) 0 0 0 0 0
0 C(17) 0 0 0 0
0 0 C(18) 0 0 0
0 0 0 C(19) 0 0
0 0 0 0 C(20) 0
0 0 0 0 0 C(21)
Coefficient Std. Error z-Statistic Prob.
C(1) -0.562845 0.156117 -3.605272 0.0003
C(2) -2.678618 0.565248 -4.738835 0.0000
C(3) 0.167219 0.066141 2.528239 0.0115
C(4) 5.668420 2.974202 1.905862 0.0567
C(5) 0.594456 0.159245 3.732954 0.0002
C(6) 3.967955 0.552159 7.186253 0.0000
C(7) -0.021128 0.080603 -0.262129 0.7932
C(8) -1.915032 3.294638 -0.581257 0.5611
C(9) -0.140701 0.167540 -0.839806 0.4010
C(10) -0.015204 0.016156 -0.941063 0.3467
C(11) -2.151999 0.669278 -3.215403 0.0013
C(12) -0.087360 0.039245 -2.226009 0.0260
C(13) 11.56806 7.454174 1.551890 0.1207
C(14) -0.795724 0.391783 -2.031030 0.0423
C(15) 0.039403 0.009232 4.267910 0.0000
C(16) 0.007819 0.001009 7.745967 0.0000
C(17) 0.006686 0.000863 7.745967 0.0000
C(18) 0.020221 0.002611 7.745967 0.0000
C(19) 0.001789 0.000231 7.745967 0.0000
C(20) 0.073057 0.009432 7.745967 0.0000
C(21) 0.003694 0.000477 7.745967 0.0000
Log likelihood 593.6875
Estimated A matrix:
1.000000 0.000000 0.000000 0.000000 0.000000 0.000000
-0.562845 1.000000 0.000000 0.000000 0.000000 0.000000
-2.678618 3.967955 1.000000 0.000000 0.000000 0.000000
0.167219 -0.021128 -0.015204 1.000000 0.000000 0.000000
5.668420 -1.915032 -2.151999 11.56806 1.000000 0.000000
0.594456 -0.140701 -0.087360 -0.795724 0.039403 1.000000
Estimated B matrix:
0.007819 0.000000 0.000000 0.000000 0.000000 0.000000
0.000000 0.006686 0.000000 0.000000 0.000000 0.000000
0.000000 0.000000 0.020221 0.000000 0.000000 0.000000
0.000000 0.000000 0.000000 0.001789 0.000000 0.000000
0.000000 0.000000 0.000000 0.000000 0.073057 0.000000
0.000000 0.000000 0.000000 0.000000 0.000000 0.003694


雷达卡



京公网安备 11010802022788号







