SAS中如何求立方根

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如题，SAS中有函数能求一个数的立方根吗？
SAS中画函数图像有什么好方法？
比如X**2+(Y-3次根号下(x**2))**2=1..

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关键词：立方根 如何 立方根

data _null_;
    a = 2;
    b = 5;
    d = a**b;
    d1 = d**(1/b);
    put a= b= d= d1= ;
run;

yongyitian 发表于 2013-11-2 22:06
data _null_;
    a = 2;
    b = 5;

thanks for your suggestion.

SAS do not provide any function for solving a root. But you can write a simple one with a data step or iml.

Many SAS procedures can be used for solving a root. The following link is an example,

https://bbs.pinggu.org/thread-1440315-1-1.html

bobguy 发表于 2013-11-4 09:42
SAS do not provide any function for solving a root. But you can write a simple one with a data step  ...

The optmodel in too advanced to be understood right away. I must study it for a while.
Thanks a million.  
貌似用乘方的几分之一更方便些。如x**(2/3).但是这样写好像不行，还得写成（x**2）**(1/3).

当时是想做函数的图像，但是只能用那种近似的模拟做的，请大家指教。
即函数x**2 +(y-(x**2)**(1/3))**2=1的图像（是个心形）。
data one;
do x = -1 to 1 by .0001;
c=2/3;
y1=(x**2)**(1/3)+sqrt(1-x**2);
y2=(x**2)**(1/3)-sqrt(1-x**2);
output;
end;
run;
goptions reset=all;
symbol1 v=point interpol=m3n90  
        color=red ci=red line=30 repeat=3;
/*symbol2 v=point color=red ci=red line=2;*/
/*symbol v=dot;*/
proc gplot data=one uniform;
plot (y1 y2)*x/overlay  haxis=axis1  vaxis=axis2 ;
axis1 offset=(0,0) order=(-1 to 1 by .1 );
axis2 offset=(0,1) order=(-1 to 1.6 by .2 );

legend label=none;
run;
quit;