求救：关于python的两个题目

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有python比较熟练的朋友帮忙看下这两道题吗？万分感激。。

Do both of these problems using at least one loop each and not using any special pre-existing functions that give you the answer with just one line of code.

1. Make a function to count the number of times a specified number is repeated in a list/array.  That means that if we have a number list

  numberList=[5, 12, 0, 7, 2, 5, 10, 9, 12, 5];

and we use the function call

  numRepeats(numberList, 5)

we get the output: 3  --- meaning 5 occurs three times in numberList.

2. Make a function that takes in a multi-dimensional array/list and returns the "diagonal" --- a list of the elements at the 1st row-and-1st column, 2nd row-and-2nd column, 3rd row-and-3rd column, etc. That means if we have a multi-dimensional array:

  multiArray = [[3, -4, 12, 5], [5, 2, 11, -5], [2, 2, 0, 5], [-5, -3, 2, 2]];

and we use the function call

  diagonal(multiArray)

we get the output [3, 2, 0, 2] .

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关键词：python Dimensional dimension Functions specified specified function problems repeated special

def numRepeats(List,Element):
    return(len([x for x in List if x==Element]))

def diagonal(multiArray):
    return([multiArray[i][i] for i in range(len(multiArray))])

def numRepeat(numlist,num):
    return numlist.count(num)

def numberRepeat(numlist,num)
   return numlist.count(num)

第一题如楼上所言， 不难
第二题也不难 用numpy的包也很方便
import numpy as np

def diagonal(multiArray)
      matrix_data = np.array(multiArray)
     return np.diag(matrix_data)

def repeatCount(seq, num):
    store = []
    for i in range(len(seq)):
        if seq[i] == num:
            store.append(seq[i])
    return len(store)

def diagonal(arr):
    store = []
    for i in range(len(arr)):
        store.append(arr[i][i])
    return store