使用Process的J-N技术做出来的结果看不懂(存在交互作用),正在写毕业论文,查了很多资料,没有找到答案,寻求大家的帮助。
********************* JOHNSON-NEYMAN TECHNIQUE **************************
Moderator value(s) defining Johnson-Neyman significance region(s)
Value % below % above
-3.9410 1.4749 98.5251
-.1158 61.6519 38.3481
Conditional effect of X on Y at values of the moderator (M)
cx6 Effect se t p LLCI ULCI
-6.1409 -.3897 .1603 -2.4315 .0153 -.7044 -.0750
-5.5409 -.3422 .1463 -2.3394 .0196 -.6293 -.0550
-4.9409 -.2946 .1324 -2.2255 .0264 -.5545 -.0347
-4.3409 -.2470 .1187 -2.0817 .0377 -.4800 -.0140
-3.9410 -.2153 .1097 -1.9635 .0500 -.4307 .0000
-3.7409 -.1995 .1052 -1.8958 .0584 -.4061 .0071
-3.1409 -.1519 .0921 -1.6488 .0997 -.3328 .0290
-2.5409 -.1043 .0796 -1.3109 .1903 -.2606 .0519
-1.9409 -.0568 .0679 -.8361 .4034 -.1901 .0766
-1.3409 -.0092 .0576 -.1599 .8730 -.1223 .1039
-.7409 .0384 .0495 .7748 .4387 -.0588 .1355
-.1409 .0859 .0449 1.9147 .0560 -.0022 .1740
-.1158 .0879 .0448 1.9635 .0500 .0000 .1758
.4591 .1335 .0448 2.9805 .0030 .0455 .2214
1.0591 .1810 .0493 3.6750 .0003 .0843 .2778
1.6591 .2286 .0572 3.9933 .0001 .1162 .3410
2.2591 .2762 .0675 4.0912 .0000 .1436 .4087
2.8591 .3237 .0792 4.0900 .0000 .1683 .4792
3.4591 .3713 .0917 4.0506 .0001 .1913 .5513
4.0591 .4189 .1047 3.9993 .0001 .2132 .6245
4.6591 .4664 .1182 3.9470 .0001 .2344 .6985
5.2591 .5140 .1319 3.8977 .0001 .2551 .7729
5.8591 .5616 .1458 3.8528 .0001 .2754 .8477
******************** ANALYSIS NOTES AND WARNINGS *************************
Level of confidence for all confidence intervals in output:
95.00
------ END MATRIX -----


雷达卡



京公网安备 11010802022788号







