在作出了空间LM检验后,不知道该如何取舍模型,可以给解释一下回归结果吗
==============================================================================
*** Binary (0/1) Weight Matrix: 480x480 - NC=30 NT=16 (Non Normalized)
==============================================================================
initial: log likelihood = 87.476877
rescale: log likelihood = 87.476877
rescale eq: log likelihood = 87.476877
Iteration 0: log likelihood = 87.476877
Iteration 1: log likelihood = 101.57122
Iteration 2: log likelihood = 103.12768
Iteration 3: log likelihood = 103.12879
Iteration 4: log likelihood = 103.12879
==============================================================================
* MLE Spatial Lag Panel Normal Model (SAR)
==============================================================================
eco = tax + lnfdi + lnpcs + fin + fd + erl + urb
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Sample Size = 480 | Cross Sections Number = 30
Wald Test = 3663.4007 | P-Value > Chi2(7) = 0.0000
F-Test = 523.3430 | P-Value > F(7 , 443) = 0.0000
(Buse 1973) R2 = 0.8859 | Raw Moments R2 = 0.9813
(Buse 1973) R2 Adj = 0.8766 | Raw Moments R2 Adj = 0.9798
Root MSE (Sigma) = 0.0960 | Log Likelihood Function = 103.1288
------------------------------------------------------------------------------
- R2h= 0.4891 R2h Adj= 0.4476 F-Test = 64.56 P-Value > F(7 , 443) 0.0000
- R2v= 0.4577 R2v Adj= 0.4136 F-Test = 56.90 P-Value > F(7 , 443) 0.0000
------------------------------------------------------------------------------
eco | Coef. Std. Err. z P>|z| [95% Conf. Interval]
-------------+----------------------------------------------------------------
eco |
tax | -.2092549 .0521457 -4.01 0.000 -.3114586 -.1070511
lnfdi | .0654107 .0110697 5.91 0.000 .0437146 .0871069
lnpcs | -.1332526 .0196252 -6.79 0.000 -.1717173 -.0947879
fin | -.0212455 .0150454 -1.41 0.158 -.0507339 .0082429
fd | -.008306 .0053935 -1.54 0.124 -.0188772 .0022651
erl | -2.854247 .5129932 -5.56 0.000 -3.859696 -1.848799
urb | .9162346 .1324721 6.92 0.000 .6565941 1.175875
_cons | 1.626772 .16022 10.15 0.000 1.312747 1.940797
-------------+----------------------------------------------------------------
/Rho | 1691.277 296.5319 5.70 0.000 1110.085 2272.469
/Sigma | .1947604 .0062877 30.97 0.000 .1824366 .2070841
------------------------------------------------------------------------------
LR Test SAR vs. OLS (Rho=0): 32.5302 P-Value > Chi2(1) 0.0000
Acceptable Range for Rho: -9.22e+03 < Rho < 8.4e+03
------------------------------------------------------------------------------
==============================================================================
*** Spatial Panel Aautocorrelation Tests
==============================================================================
Ho: Error has No Spatial AutoCorrelation
Ha: Error has Spatial AutoCorrelation
- GLOBAL Moran MI = 0.1554 P-Value > Z( 4.051) 0.0001
- GLOBAL Geary GC = 0.9433 P-Value > Z(-0.824) 0.4099
- GLOBAL Getis-Ords GO = -0.0000 P-Value > Z(-4.051) 0.0001
------------------------------------------------------------------------------
- Moran MI Error Test = 6.30e+04 P-Value > Z( 1.6e+06) 0.0000
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- LM Error (Burridge) = 13.4157 P-Value > Chi2(1) 0.0002
- LM Error (Robust) = 14.2632 P-Value > Chi2(1) 0.0002
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Ho: Spatial Lagged Dependent Variable has No Spatial AutoCorrelation
Ha: Spatial Lagged Dependent Variable has Spatial AutoCorrelation
- LM Lag (Anselin) = 0.0021 P-Value > Chi2(1) 0.9631
- LM Lag (Robust) = 0.8496 P-Value > Chi2(1) 0.3567
------------------------------------------------------------------------------
Ho: No General Spatial AutoCorrelation
Ha: General Spatial AutoCorrelation
- LM SAC (LMErr+LMLag_R) = 14.2653 P-Value > Chi2(2) 0.0008
- LM SAC (LMLag+LMErr_R) = 14.2653 P-Value > Chi2(2) 0.0008
------------------------------------------------------------------------------
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end of do-file
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