no | seq | X001 | X002 | X003 | X004 | X101 | X102 | X103 | X104 | Y001 | Y002 | Y003 | Y004 | Y101 | Y102 | Y103 | Y104 |
1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 5 | 5 | 5 | 5 | 0 | 0 | 0 | 0 |
2 | 2 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 4 | 5 | 5 | 5 | 0 | 0 | 0 | 0 |
3 | 2 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 4 | 5 | 5 | 5 | 2 | 2 | 0 | 0 |
4 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 4 | 5 | 5 | 5 | 0 | 0 | 0 | 0 |
5 | 1 | 1 | 0 | 0 | 1 | 1 | 1 | 0 | 2 | 2 | 4 | 4 | 4 | 0 | 0 | 0 | 0 |
6 | 1 | 1 | 0 | 1 | 0 | 1 | 1 | 0 | 3 | 3 | 5 | 5 | 5 | 1 | 1 | 0 | 0 |
7 | 2 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 5 | 5 | 4 | 5 | 2 | 2 | 1 | 0 |
8 | 2 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 5 | 5 | 5 | 5 | 2 | 3 | 0 | 0 |
9 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 4 | 5 | 5 | 5 | 1 | 1 | 0 | 0 |
10 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 5 | 5 | 5 | 5 | 0 | 0 | 0 | 0 |
11 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 4 | 4 | 4 | 5 | 2 | 2 | 0 | 0 |
12 | 2 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 5 | 5 | 5 | 5 | 3 | 4 | 0 | 0 |
13 | 2 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 4 | 4 | 4 | 4 | 0 | 0 | 0 | 0 |
14 | 2 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 5 | 5 | 5 | 5 | 0 | 0 | 0 | 0 |
15 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 5 | 5 | 5 | 5 | 1 | 0 | 0 | 0 |
16 | 2 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 5 | 5 | 5 | 5 | 1 | 0 | 1 | 0 |
17 | 2 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 5 | 5 | 5 | 5 | 1 | 1 | 0 | 0 |
18 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 4 | 5 | 5 | 5 | 1 | 1 | 0 | 0 |
19 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 4 | 5 | 5 | 5 | 0 | 0 | 0 | 0 |
20 | 2 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 4 | 5 | 5 | 5 | 0 | 0 | 0 | 0 |
no代表接受测试人的编号,seq代表接受的处理(其中1代表先接受A处理,然后B处理;2代表先接受B处理,然后A处理);
X001-X004代表第一阶段处理前的分值,X101-X104代表第一阶段处理后的分值;
Y001-Y004 代表第二阶段处理前的分值,Y101-Y104代表第二阶段处理后的分值。
以上数据是模拟的,实际遇到的数据量比这个大很多。
求教:①如何将以上数据处理成为可以进行二阶段交叉设计方差分析的资料。
②整理后的数据,用以下过程分析是否可以。
proc glm ;
class no group stage seq;model k1=k0 group stage treat no(seq)/ss3;
quit;
其中,k1代表处理后的值,no代表编号,seq代表处理顺序,group代表接受的处理,stage代表阶段,k0代表处理前的值。
非常感谢!!!